1/25=(1/125)^(2x-3)

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Solution for 1/25=(1/125)^(2x-3) equation: 



1/25=(1/125)^(2x-3)

We move all terms to the left:

1/25-((1/125)^(2x-3))=0



Domain of the equation: 125)^(2x-3))!=0

x∈R



We add all the numbers together, and all the variables

-((+1/125)^(2x-3))+1/25=0

We calculate fractions


()/125^2x+125x/125^2x=0

We multiply all the terms by the denominator


125x+()=0

We add all the numbers together, and all the variables

125x=0

x=0/125

x=0

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